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algebra 2

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Find two negative numbers such that the sum of their squares is 170 and twice the square of the first minus 3 times the square of the second is 95

  • algebra 2 -

    a^2+b^2 = 170
    2a^2-3b^2 = 95
    substituting,
    2a^2-3(170-a^2) = 95
    5a^2 - 510 = 95
    5a^2 = 605
    a^2 = 121

    a = -11
    b = -7

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