algebra 2
posted by aaron .
Find two negative numbers such that the sum of their squares is 170 and twice the square of the first minus 3 times the square of the second is 95

a^2+b^2 = 170
2a^23b^2 = 95
substituting,
2a^23(170a^2) = 95
5a^2  510 = 95
5a^2 = 605
a^2 = 121
a = 11
b = 7