Pre-Calc

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How do I solve this via partial fraction decomposition?

(x^2+9)/(x^4-2x^2-8)

  • Pre-Calc -

    The bottom factors to (x^2-4)(x^2+2)
    = (x+2)x-2)x^2+4)

    so let
    (x^2+9)/(x^4-2x^2-8) = A/(x+2) + B/(x-2) + C/(x^2+2)

    ( A(x-2)(x^2+2) + B(x+2)(x^2+2) + C(x+2)(x-2) ) = x^2 + 9
    since the denominators on the left and right are the same.

    This must be true for all values of x

    let x=2 ---> 24B = 13 or B = 13/24
    let x=-2 --> - 24A = 13 or A = -13/24
    let x = 1 --> -3A + 9B - 3C = 10
    sub in the values of A and B to get
    C = -7/6

    so (x^2+9)/(x^4-2x^2-8)
    = -13/(24(x+2)) + 13/(24(x-2)) - 7/(6(x^2+2))

  • Pre-Calc -

    Thank you. But what about the "Cx+D" part?

  • Pre-Calc -

    You are correct, Micki, that there is supposed to be a (Cx+D) over a quadratic denominator. Luckily, in this case, C=0, so it worked out. Had it been otherwise, I'm sure it would have become apparent.

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