Precalc with Trig
posted by Natalie .
What value(s) of x from 0 to 2pi solve the following equation: cos squared x  cos x  6 = 0
Respond to this Question
Similar Questions

Trig
If cosx = 10/19 an pi < x < 2pi, find the exact value of cos x/2 Use the double angle formula. Cos 2Y= sin^2 Y  cos^2Y = 12Cos^2 Y. let y= x/2, and 2Y=x 
Math  Solving for Trig Equations
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360  cos^2x  1 = sin^2x  Attempt: cos^2x  1  sin^2x = 0 cos^2x  1  (1  cos^2x) = 0 cos^2x  1  1 + cos^2x = 0 2cos^2x  2 = 0 (2cos^2x/2)= … 
trig
2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3π] So I need to find general solutions to solve the equation. But do I eliminate cos(x), like this... 2sin(x)cos(x)+cos(x)=0 2sin(x)cos(x)= cos(x) 2sin(x) = … 
Trig
How would I do this problem? Verify that each equation is an identity. cos^2x+tan^2xcos^2x=1 the ^2 is just saying squared. ex. cos^2x is cosine squared x 
Trig
Solve for 0<x<2pi > (2radical2)cos^2(x)(radical22)cos(x)1=0 
precalc/trig
olve for the interval [0, 2pi]. cos(x+ pi/4)+cos(x pi/4)=1 
Precalc with Trig
What value(s) of theta (0 less than or equal to theta less than or equal to 2pi) solve the following equation: cos squared theta  cos theta  6 = 0 
trig
Find all real numbers in the interval [0,2pi) that satisfy the equation. cos^2 x+2 cos x+1 = 0 
Precalc+trig
Solve tan(40/90) for the double angle cos(2theta). I know I use the x^2 + y^2 = r^2 formula and cos(2theta) = cos^2theta  sin^2theta. But I don't understand my answer 
Trig
Find all solutions of the equation in the interval [0,2pi) 2 cos^2 xcos x = 0 2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) 1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong?