Please Reiny Solve it For me Again! please......
posted by Seth
Solve for the value of x: log5(x2)+log8(x4)=Log6(x1)..For your information that 5,8 and 6 are bases not just multipliers. Thank you.

Steve
log 5(x2) + log 8(x4) = log 6(x1)
log [5(x2)*8(x4)] = log 6(x1)
so, if the logs are =, so are the expressions, and we have
40(x2)(x4) = 6(x1)
20(x2)(x4)  3(x1) = 0
20x^2  123x + 163 = 0
now just use the quadratic formula to see the solutions. Check to be sure the values are defined in the original expressions. 
Seth
6log(x^2+1)x=0
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