Please Reiny Solve it For me Again! please......
posted by Seth .
Solve for the value of x: log5(x2)+log8(x4)=Log6(x1)..For your information that 5,8 and 6 are bases not just multipliers. Thank you.

Please Reiny Solve it For me Again! please...... 
Steve
log 5(x2) + log 8(x4) = log 6(x1)
log [5(x2)*8(x4)] = log 6(x1)
so, if the logs are =, so are the expressions, and we have
40(x2)(x4) = 6(x1)
20(x2)(x4)  3(x1) = 0
20x^2  123x + 163 = 0
now just use the quadratic formula to see the solutions. Check to be sure the values are defined in the original expressions. 
Please Reiny Solve it For me Again! please...... 
Seth
6log(x^2+1)x=0
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