A 337-\rm mL sample of unknown \rm HCl solution reacts completely with \rm Na_2CO_3 to form 17.1g \rm CO_2. What was the concentration of the \rm HCl solution?
To determine the concentration of the HCl solution, we need to use stoichiometry and the information given.
Let's break down the information given:
- The volume of the HCl solution is 337 mL.
- The reaction between HCl and Na2CO3 results in the formation of CO2 as a product.
- The mass of CO2 produced is 17.1 g.
To solve the problem, we need to follow these steps:
Step 1: Write the balanced chemical equation for the reaction between HCl and Na2CO3:
2 HCl + Na2CO3 -> CO2 + 2 NaCl + H2O
Step 2: Since we know the mass of CO2 produced (17.1 g), we need to convert this mass to moles of CO2. To do this, we need to know the molar mass of CO2, which is approximately 44.01 g/mol.
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Moles of CO2 = 17.1 g / 44.01 g/mol
Step 3: Use the balanced equation to determine the mole ratio between HCl and CO2. According to the equation, the ratio is 2 moles of HCl to 1 mole of CO2.
Moles of HCl = (Moles of CO2) × (2 moles of HCl / 1 mole of CO2)
Step 4: Calculate the concentration of the HCl solution using the following formula:
Concentration = (Moles of HCl) / (Volume of HCl solution in liters)
Convert the volume of the HCl solution from mL to liters by dividing it by 1000.
Concentration = (Moles of HCl) / (Volume of HCl solution in liters)
Concentration = (Moles of HCl) / (337 mL / 1000)
Now you have all the steps necessary to calculate the concentration of the HCl solution. Simply plug in the values and perform the calculations.