# Trig

posted by .

Solve the trig equation exactly over the indicated interval.

tanθ = 0, all real numbers

I know the answer is πn, but I don't understand how they got this. I get that tanθ = 0 on π and 2π on the unit circle, so did they just put n on the end of π because of this?

• Trig -

tanØ = sinØ/cosØ = 0

in sinØ/cosØ = 0 , that is only possible if sinØ = 0
and you should know that the basic sine curve has zeros at 0 , π and 2π

since the period of sinØ = π,
a new answer can be obtained by simply adding/subtracting multiples of π (or nπ) to any anwer
So why not start with 0 + nπ = nπ

• Trig -

Use trigonometric identities to solve tan(2θ)+tan(θ)=0 exactly for 0≤θ≤π. If there is more than one answer, enter your answers as a comma separated list

## Respond to this Question

 First Name School Subject Your Answer

## Similar Questions

1. ### trig

cosθ =5/13 with -π/2 < θ <0 find each of the following sin( θ - 5π/4) cos( θ - 11π/6) tan( θ + 5π/4) can some1 explain to me how to do these?
2. ### trigonometry

tanθ= -2sqrt10/3 and π/2<θ< π find a. cos(-θ) b. cos(11π/6 - θ) c.sin2θ d.tanθ/2 can some please explain to me how to solve these questions?
3. ### trigonometry

given tanθ= -2√10/3 and π/2<θ< π find: sin2θ tan θ/2 given sinθ=-5/13 and π<θ<3π/2 find sin2θ cos( θ-4π/3) sin(θ/2) can some1 explain this to me …
4. ### mathematics

given tanθ= -2√10/3 and π/2<θ< π find: a.sin2θ b.tan θ/2 could some1 help me with these 2 they're the only ones i couldn't get
5. ### Trig

The set of solution(s) of 2 cos^2 (θ) - 13 cos(θ) + 6 = 0 that is(are) in the interval (0,π/2) is one of following a. {π/6} b. {π/3} c. {π/4} d. {π/3, π/6} e. {π/6, π/4}
6. ### Solving Trig equation

Solve the trig equation exactly in the interval 0≤x≤2π. tan x + tan π/3 ------------------ = square root 3 1 - tan x tan π/3
7. ### trig

find cos(θ)ˏsin(θ)ˏtan(θ), if cot (2θ)=5/12 with 0≤2θ≤π Answer this Que
8. ### Precalc/Trig

Sorry there are quite a few problems, but I just need to know if these are correct (and if they aren't, where I went wrong): 1. Solve these equations. tanθ = -√3 θ = 2π/3 + kπ θ = 5π/3 + kπ …
9. ### calculus

1. what trig function has an amplitue of 1 and negative values for angles between π/2 and π?
10. ### Pre-Cal (Help Plz!)

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.) (tan^2θ-9)(2cosθ+1)=0 θ=__________________ …

More Similar Questions