1. You have a large wind tunnel of cross-sectional area 0.61[m2]. The wind speed is 4[ms-1]. Assume air density is 1 [kgm-3]. The Drag is 2.3[N].
What is the coeffecient of drag for the shape that has diameter 7.32[cm]? .
Use three sig. figs. or N/A if there is not enough information.
2. You have a large wind tunnel of cross-sectional area 0.95[m2]. You have a set of shapes that are all the same shape except they each have a different cross-sectional area. The wind speed is held constant at 3.2[ms-1]. Assume air density is 1 [kg m-3]. The slope of Drag versus Area for this data is 0.45. [Slope units left out purposefully by me for sake of next question.]
What is the coeffecient of drag for the shape? .
Use three sig. figs. or N/A if there is not enough information.
3. The slope from the plot of Drag versus Area in the question above has units of
[N]
[m2]
[kgm-3]
No units
[Nm-2]
1. To find the coefficient of drag, we can use the equation:
Coefficient of drag = (2 * Drag) / (Air density * Wind speed^2 * Cross-sectional area)
Plugging in the given values:
Coefficient of drag = (2 * 2.3) / (1 * 4^2 * 0.61)
Coefficient of drag = 0.0938
Therefore, the coefficient of drag for the shape with a diameter of 7.32 cm is approximately 0.094.
2. To find the coefficient of drag for the shape, we can use the equation:
Coefficient of drag = (Slope of Drag versus Area) / (Air density * Wind speed^2)
Plugging in the given values:
Coefficient of drag = 0.45 / (1 * 3.2^2)
Coefficient of drag = 0.0443
Therefore, the coefficient of drag for the shape is approximately 0.044.
3. The slope from the plot of Drag versus Area in the question above has units of [N/m2].