algebra
posted by dina .
How do I solve this problem? 3x2/3x=4/3

3x2/3x=4/3
7/3x = 4/3
x = (4/3) / (7/3)
x = (4/3) * (3/7)
x = 12/21 = 4/7 
Thank you Ms.Sue, but could you please show me how you got 7/3x?

I think this problem is really
(3x  2) / 3x = 4 / 3
[cross multiply]
3(3x  2) = 4 * 3x
9x  6 = 12x
9x 6 + 6 = 12x +'6
9x = 12x + 6
9x  12x = 12x + 6  12x
3x = 6
x = 2 
3x  2/3x = 2 1/3x
2 1/3 = 7/3 
Thanks Jake, but the ans. to this problem is x=4/7, so the set up is... 3x2/3x4/3.

Thank you so much Ms. Sue!
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