# Analytical chemistry

posted by .

A 25.0-mL solution of 0.0660 M EDTA was added to a 33.0-mL sample containing an unknown concentration of V3 . All V3 present formed a complex, leaving excess EDTA in solution. This solution was back-titrated with a 0.0450 M Ga3 solution until all the EDTA reacted, requiring 13.0 mL of the Ga3 solution. What was the original concentration of the V3 solution?

• Analytical chemistry -

EDTA reacts with both V3+ and Ga3+ in a 1:1 stoichiometric ratio.
Therefore, the moles of EDTA added is equal to the sum of the moles of V3+ present and Ga3+ added.
moles of EDTA= moles V3 + moles of Ga3
(0.025 L)(0.0660 M EDTA)= (x moles of V3) + (0.013 L)(0.0450 M Ga3)
moles of V3= 0.001065
M of V3 = 0.001065 moles / 0.033 L
M of V3 = 0.032 moles/L

## Similar Questions

1. ### chemistry

25.00 mL aliquots of the solution from Part 1 are titrated with EDTA to the Eriochrome Black T end point. A blank containing a small measured amount of Mg2+ requires 2.60 mL of the EDTA to reach the end point. An aliquot to which the …
2. ### Chemistry

Sally is goint to determine the quantity of MgSO4 by titrating the Mg2+ ions using EDTA. What is the concentration of Mg2+ (in mmol/L) in the sample if it takes 22.9 mL of EDTA solution with concentration of 0.01108 mol/L to titrate …
3. ### Chemistry

A 25.00 ml sample of a standard solution containing 1 g of CaCO3/L required 25.20 ml of EDTA to fully complex the Ca present. Calculate the volume of EDTA stoichiometrically equivalent to 1.0 mg of CaCO3. From the volume of EDTA required …
4. ### Chemistry

The reaction of a metal ion, M^2+, with EDTA is given in the following equation: M^2+(aq) + Y^4-(aq) <==> MY^2-(aq) The EDTA was standardized with a 0.04 M Zn^2+ solution. 25.05 mL of EDTA solution was used to titrate the Zn^2+ …
5. ### analytical chemistry

An EDTA solution is standardized against a solution of primary standard CaCO3 (0.5622 g dissolve in 1000 ml of solution) and titrating aliquots of it with the EDTA. If a 25.00 ml aliquot required 21.88 ml of the EDTA, what is the concentration …
6. ### chemistry

Assume that 50ml of 0.01M edta solution were added to 25ml of co solution and the excess edta required 20ml of 0.005M mg solution. Calculate ppm co+ present. The answer 942ppm Bob helps me
7. ### chemistry

0.5g of fuming h2s04 oleum is diluted with water. This solution is completely neutralized by 26.7ml of 0.4N naoh. Find the percentage of free s03 in the smaple solution. The answer 20.6% Assume that 50ml of 0.01M edta solution were …
8. ### analytical chemistry

A solution containing both Fe 3+ and Al 3+ can be selectively analyzed for Fe 3+ by buffering to a pH of 2 and titrating with EDTA. Th e pH of the solution is then raised to 5 and an excess of EDTA added, resulting in the formation …
9. ### Chem 2

A 100-mL sample of water is titrated with EDTA solutions in problem 2. The same amount of Mg2+ is added as previously, and the volume of EDTA required is 31.84mL. What volume of EDTA is used in titrating the Ca2+ in hard water?
10. ### Chemistry

Step 1: A 12.70mL sample of cyanide solution was mixed with 25.00mL of a solution of nickel ions at an appropriate pH to form the Ni-cyanide complex. The resulting solution was titrated cs 0.0130M EDTA and required 10.10mL to reach …

More Similar Questions