# Please solve it for me!! Please...Maths

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Solve for the value of x: 6log(x^2+1)-x=0

• Please solve it for me!! Please...Maths -

6log(x^2+1)-x=0

6 log(x^2 + 1) = x
log(x^2 + 1) = x/6
x^2 + 1 = e^(x/6)
wow ....

try Wolfram, since there is no "nice" way to solve this
http://www.wolframalpha.com/input/?i=x%5E2+%2B+1+%3D+e%5E%28x%2F6%29

It says: x = appr 0 or x = appr .169 or x = appr 45.93

testing:
if x = 0
LS = 6ln(1) - 0 = 0 = RS ----> x = 0
if x = .169
LS = 6ln(1.028561) - .169
= -.000035 and RS = 0 ---->not bad, x = appr .169
if x = 45.93
LS = 6ln(2110.5649) - 45.93
= -.0017.. close to zero -----> x = appr 45.93

all three answers work!!!!

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