Post a New Question

Precalculus

posted by .

Verify the identities.

Cos^2x - sin^2x = 2cos^2x - 1

When verifying identities, can I work on both side?
Ex.
1 - sin^2x - sin^2x = 1 - 2sin^2x
1 - 2sin^2x = 1 - 2sin^2x

  • Precalculus -

    cos ^ 2 ( x ) - sin ^ 2 ( x ) = 2 cos ^ 2 ( x ) - 1 Subtract cos ^ 2 ( x ) to both sides

    cos ^ 2 ( x ) - sin ^ 2 ( x ) - cos ^ 2 ( x ) = 2 cos ^ 2 ( x ) - 1 - cos ^ 2 ( x )

    - sin ^ 2 ( x ) = cos ^ 2 ( x ) - 1 Add 1 to both sides

    - sin ^ 2 ( x ) + 1 = cos ^ 2 ( x ) - 1 + 1

    1 - sin ^ 2 ( x ) = cos ^ 2 ( x )

    ________________________________________

    Remark:

    1 - sin ^ 2 ( x ) = cos ^ 2 ( x )
    ________________________________________


    So :

    cos ^ 2 ( x ) = cos ^ 2 ( x )

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question