Chemistry

posted by .

X^2+ + 2e- -> X(s) E=1.73V
Y^2+ + 2e- -> Y(s) E=0.40v

Which pair of species would react under standard conditions?
X^2+ and Y^2+
X and Y^2+
X and Y
X^2+ and Y

Would it be X and Y because the E is positive?

  • Chemistry -

    I don't think X + Y will be positive. In fact they won't react at all.
    X^2+ + Y ==> X + Y^2+ 1.73-0.40 = +?

  • Chemistry -

    So would it be X^2+ and Y^2+?

  • Chemistry -

    No. How do you get a reaction out of X^2 + Y^2?
    X^2+ + 2e ==> X
    Y^2+ + 2e = Y
    Both of them are being reduced. In a reaction an oxidation is ALWAYS accompanied with a reduction.
    So X and Y won't react.
    X^2+ + Y^2+ won't react.
    The only possibilities are the second and fourth choices and I gave you the right choice in my first response.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    For there reaction system involving the species in the table below, what conclusion is justified for standard state conditions?
  2. chem

    would you expect 2-chlorobutane to react faster or slower than 2-bromobutane under sn1 conditions?
  3. chem

    Would you expect 2-chlorobutane to react faster or slower than 2-bromobutane under Sn1 conditions?
  4. ethics

    If you are an employee of a business, and learn that it is violating the law, what would you do in this situation?
  5. Chemistry

    Which pair of ions will be most likely to react at standard state conditions?
  6. CONFUSING QUESTION PLEASE HELP

    Which one of the following species will react with Sn at standard state conditions?
  7. HELP! CHEMISTRY

    Which one of the following species will react with Sn at standard state conditions?
  8. Chemistry Help Please

    Which pair of ions will be most likely to react at standard state conditions?
  9. Chemistry

    What would the potential of a standard hydrogen (S.H.E.) electrode be if it was under the following conditions?
  10. AP Chem

    1. Van't Hoff factors depend on the concentrations of the dissolved solute species. Why would a dilute solution have a Van't Hoff factor closer to the ideal value?

More Similar Questions