posted by John .
Titration of 0.6500g of an acid requires 182.42 mL of 6.020x10^-3 N NaOH to reach the endpoint. What is the mass of an equivalent of this acid?
A mighty weak acid to be used for titration in my opinion.
mL x N x milliequivalent weight = grams.
You want to find the mew, then multiply by 1000 for equivalent weight.