Algebra Multiple choice revised!! HELP
posted by Kris .
I have a few questions I need help with! Please explain if my answer was not right how you got to it. I got 1.) B 2.) A 3.) C
1. Solve the system by triangularizing the augmented matrix and using back substitution. If the system is linearly dependent, give the solution in terms of a parameter.
C.) Coincident dependence; (x,y,z)|3x+yz=4}
D.) No solution, inconsistent
2. Solve the system by triangularizing the augmented matrix and using back substitution.
3. What row operation would produce zero beneath the first entry in the diagonal?
1 2 | -1
8 -2 | -2
A.) 8R1-R2--> R2
B.) -8R1-R2 -->R2
C.) -R1+R2 --> R2
D.) 8R1-R2 --> R2
#1 - look at the equations. They are all the same. That is, they are multiples of each other. So, (C)
#2. (D) Did you check your answer to see whether it actually fits the equations?
#3. (A) and (D) are the same, so I suspect a typo. Anyway, you want to get rid of the 8, so you know you have to multiply R1 by 8 and subtract R2.