Maths

posted by .

Solve for X: log4(3x-7)^2 = 10

  • Maths -

    (3x-7)^2 = 4^10
    3x-7 = ±1024
    now it's easy

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra II

    Solve, round to four decimal places if necessary: log4(x-9)=2 Answer: x-9=4^2 x-9=16 x=11 log4(z)+log4(z-3)=1 Answer: z+z-3=1 2z=4 z=2 Thanks for checking my work.
  2. Logarithms

    Solve log4 x + log4(x-2)=log4(15) I know how do the example in my book but I don't know what I'm doing wrong here. log4 x + log4(x-2)=log4(15) log4 [x + log4(x-2)]=log4(15) (x^2 + x)=4 x^2 + x-4=0
  3. math

    Solve the equation algebraically. Round the result to three decimal places. log4 x - log4(x-1) = 1/2 I have no idea how to do this. Please help!
  4. Algebra 2

    Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks
  5. Math(Please check)

    solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
  6. Math

    solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
  7. Trig/Pre-Calc

    Could someone please help me on this problem. I'm really confused, and this assignment is due tomorrow. Solve the logarithmic equation algebraically. Approximate the result to three decimal places. log4x-log4(x-1)=1/2 To start off …
  8. Math Algebra 2

    #4. Express the logarithm in terms of log2M and log2N: log2 1/MN #5. Simplify: log4 3 - log4 48 #6. Solve the equation: loga x = 3/2loga 9 + loga 2 #7. Solve the equation: logb (x2 + 7) = 2/3logb 64 #8. Solve the equation: loga (3x …
  9. precalc

    I don't understand how to do these w/o calc. I tried to write it in a way that will make someone understand how to read it. Hope I typed it clear enough.Thanks so much for the help anyone! How to find the exact value of logarithm: …
  10. Precalc

    Using logarithms to rewrite the expression: 1.) log4.(4)^3x= 2.) 6 log6 36= 3.) 3 log 2 1/2= 4.) 1/4 log4 16

More Similar Questions