pre calculus

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use the seven step method to graph the following rational function:
f(x)=3x^2+x-4/2x^2-5x

a. determine the symmetry of the function.
b. find the x and y intercepts.
c. find the verticle asymptote
d.find the horizontal asymptote
e.plot the points between and beyond the x intercept and verticle asymptote.

I don't get any of this. help me please?

  • pre calculus -

    How can you not get any of this?

    symmetry may be a bit tough:
    f(x) = (3x+4)(x-1) / x(2x-5)
    I don't see any symmetry there at all.

    the intercepts are easy, right?

    Vertical asymptote where denominator si zero

    horizontal asymptote is y when x gets huge. There, all the small powers of x become insignificant, and you are working with
    3x^2/2x^2 = 3/2

    visit wolframalpha.com and enter

    (3x^2+x-4)/(2x^2-5x)

    for a graph

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