Physics
posted by Joshua .
A brick is thrown off a building at a 25 degree angle at 10m/s, it lands 40 meters away, How high is the building?

Time of flight = t = (40 m)/(Vo*cos25)
= 4.41 s
since the horizontal velocity component is constant.
Vo*sin25*t  (1/2)gt^2 = (Height)
since the vertical location is
(Height) when it hits the ground
Height = 4.9 t^2  4.226 t
= 95.3  18.6 = 76.7 m
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