Chemistry Solubility help!!!!!!!!!
posted by Sally .
[HCl] = 0.1388 M
We placed 0.5 g Ca(OH)2 in 100 mL of the following solutions:
Flask A: Distilled Water (7.4 mL of HCl needed to titrate)
Flask B: 0.05 NaOH (12.1 mL of HCl needed to titrate)
Flask C: 0.025 NaOH (10.8 mL of HCl needed to titrate)
Flask D: 0.0125 NaOH (8.9 mL of HCl needed to titrate)
QUESTION is to calculate the following for each flask:
[OH-]eq from titration
[OH-]0 from original solution
[OH-] from Ca(OH2)
[Ca2+]eq from Ca(OH)2
Ksp = [Ca2+]eq * [OH-]eq
Please teach me how to get answers for one of the flasks, then I could finish the rest :)
You don't have units on the NaOH. 0.05 what? 0.025 what? 0.0125 what? And that may not be all the what? If those are M then what are the volumes? If they are grams that's ok.