# Calculus 1A

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I am trying to find:
dy/dx for y = sec(tan x)

I have the answer, but I have no idea how to get there. I know that the derivative of sec x = sec x tan x and that the derivative of tan x is sec^2 x. But sec doesn't have an x, so ...?

• Calculus 1A -

d/dx secu = secu tanu du/dx, so
y' = sec(tanx) tan(tanx) sec^2(x)

• Calculus 1A -

thanks!!!!!!

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