chemistry

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A certain weak base has a Kb of 8.40 × 10-7. What concentration of this base will produce a pH of 10.34?

  • chemistry -

    pH = 10.34
    pOH = 14-10.34 = 3.66
    Then (OH^-) = about 2E-4 but that's only an estimate.
    ........BOH ==> B+ + OH^-
    I........x.......0.....0
    C.......-y.......y.....y
    E.......x-y .....y.....y

    Kb = 8.4E-7 = (B^+)(OH^-)/(HB)
    You know y and Kb, substitute into Kb expression and solve for x.

  • chemistry -

    I don't understand what Y and X are supposed to be

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