Physics

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1. At what height above the earth is the free-fall acceleration 30% of its value at the surface?


2. What is the speed of a satellite orbiting at that height?

  • Physics -

    1.
    g =GM/R²
    g₁=GM/(R+h)²
    g₁/g=30/100= GM R²/(R+h)²GM =>
    0.3= R²/(R+h)²
    Solve for “h” (Earth’s radius is R = 6.378•10⁶ m)
    2.
    mv²/(R+h)= GmM/(R+h)²
    v=sqrt { GM/(R+h)}

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