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Calculate the pH at the equivalence point in titrating 0.100 M solutions of each of the following with 0.080 M NaOH.

chlorous acid (HClO2)

benzoic acid (C6H5COOH)

  • chem -

    NaOH + HClO2 ==> NaClO2 + H2O so the pH at the equivalence point is determined by the hydrolysis of NaClO2 (actually the hydrolysis of the ClO2^-. The (ClO2^-) = 0.0444M. If you don't know how to do this I can show you.
    .........ClO2^- + HOH ==>HClO2 + OH^-
    I........0.0444..........0........0
    C.........-x..............x........x
    E.......0.0444-x..........x........x

    Kb for ClO2^- = (Kw/Ka for HClO2) = (x)(x)/(0.0444-x)
    Solve for x = (OH^-) and convert to pH.

  • chem -

    i am confused how you got the .0444?

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