Chemistry

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A solution contains 25 mmol of H3PO4 and 10. mmol of NaH2PO4. What volume of 2.0 M NaOH must be added to reach the second equivalence point of the titration of the H3PO4 with NaOH?

  • Chemistry -

    Look at titrating the first H, then double it.
    H3PO4 + NaOH ==> NaH2PO4 + H2O
    mols H3PO4 = 25 mmols.
    So you will need 25 mmols NaOH to react with the first H of H3PO4.
    M NaOH = mols NaOH/L NaOH
    2.0M = 25 mmols/mL
    mL = 25/2.0 = 12.5 mL.

    So it will take 25 to neutralize the second H of H3PO4 (and 37.5 mL to neutralize the 3rd H although you probably wouldn't know when you were there.)

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