a loaded cart, mass220-kg is pulled across the ground with the force of300n acting at angle 37 degree with the horizontal. how much work is done in moving the cart 20m?
Fc = m*g = 220kg * 9.8N/kg = 2156 N. =
Force of the cart.
Work = Fc * D = 300*cos37 * 20=4792 J.
NOTE:
The force of the cart(Fc) is not needed.
To find the work done in moving the cart, we can first calculate the horizontal component of the force in the direction of motion.
Step 1: Calculate the horizontal component of the force:
The horizontal component of the force can be found by multiplying the magnitude of the force by the cosine of the angle between the force vector and the horizontal direction.
Horizontal force component = Force * cos(angle)
Horizontal force component = 300 N * cos(37°)
Step 2: Calculate the work done:
The work done is equal to the product of the magnitude of the horizontal force component and the displacement.
Work done = Horizontal force component * displacement
Work done = (300 N * cos(37°)) * 20 m
Now, let's calculate the work done:
Work done = (300 N * cos(37°)) * 20 m
Work done ≈ 2315.76 Joules
Therefore, approximately 2315.76 Joules of work is done in moving the loaded cart 20 meters.