posted by J .
A coffee cup calorimeter contains 25.0 grams water at 23.8 C
A 5.00g sample of an unknown metal at an initial temperature of 78.3 C was dropped into the calorimeter.
The final temperature of mixture was 46.3 C.
Calculate the specific heat of the metal. The specific heat of ater is 4.184 J/ (g C)?
You will need the following equation:
heat lost=heat gain, that is,
c1=4.184 J/ (g C)
Solve for c2,
This must be a made up problem. I don't know that I've seen anything with a specific heat of this magnitude.