Calc

posted by .

f(x)=2ln(x^2+3)-x Domain [-3,5]

how do i find the absolute maximum value of this?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calc

    Let f be the function given by f(x)=2ln(x^2+3)-x with domain -3 is less than or equal to x which is less than or equal to 5 a) Find the x-coordinate of each relative maximum point and each relative minimum point of f. Justify your …
  2. Calculus (pleas help!!!)

    Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum …
  3. Calculus (pleas help!!!)

    Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum …
  4. math/calculus

    f(x)= the absolute value of x^2-6x-7 a) Find a piecewise defined function that has no absolute value involved b) Let g(x)=f(x) for x is greater than or equal to 7 find an expression of g^-1(x) c. give the domain and range of g^-1(x)
  5. Differential Equations (Another) Cont.

    For the following initial value problem: dy/dt=1/((y+1)(t-2)) a)Find a formula for the solution. b) State the domain of definition of the solution. c) Describe what happens to the solution as it approaches the limit of its domain of …
  6. Calc

    f(x)=2ln(x^2+3)-x Domain [-3,5] how do i find the absolute maximum value of this?
  7. Calc

    f(x)=2ln(x^2+3)-x Domain [-3,5] how do i find the absolute maximum value of this?
  8. Calculus

    Find the absolute extrema of the function. (Round your answer to three decimal places.) f(x) = xe-x2 on [0,2] Absolute maximum value: at x = Absolute minimum value: at x =
  9. Calculus

    Find the absolute extrema of the function. (Round your answer to three decimal places.) f(x) = xe^-x2 on [0,2] Absolute maximum value: at x = Absolute minimum value: at x =
  10. Math(Calculus)

    Im having a real difficult time solving this question. Find the absolute extrema of the function. h(x) = e^x^(2) - 4 on [-2,2] Absolute maximum value: at x = Absolute minimum value: at x =

More Similar Questions