stats.

posted by .

The mean number of bumped airline passengers per day is 1.35 and the standard deviation is 0.25. For a random selection of a group of 40 days, what is the probability that the mean of bumped passengers for the 40 days will be between 1.25 and 1.50?

  • stats. -

    Use this z-score formula for this problem:

    z = (x - mean)/(sd/√n)

    x = 1.25, 1.50
    mean = 1.35
    sd = 0.25
    n = 40

    Calculate two z-scores, then use a z-table to determine probability between the two scores.

    I hope this will help get you started.

  • stats. -

    z=(1.25-1.35)/(0.25sqrt40)= -0.0791
    z=(1.50-1.35)/(0325sqrt40)= 0.0791

    but not sure how to read the z scores I don't know if it would be.5000-.5000 or what can someone please help me on the z scores for -0.0791 and 0.0791

  • stats. -

    SD/√n = .25/6.3246 = .039528192 = .04

    Z = (1.25-1.35)/.04 = -.10/.04 = -2.5

    Z = (1.50-1.35)/.04 = .15/.04 = ?

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of both Z scores between those Z scores and mean. Add the two together.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Statistics

    The number of passengers on the Carnival Sensation during one-week cruises in the Caribbean follows the normal distribution. The mean number of passengers per cruise is 1,820 and the standard deviation is 120. a. What percent of the …
  2. statistics

    In response to the increasing weight of airline passengers, the Federal Aviation Administration in 2003 told airlines to assume that passengers average 190 pounds in the summer, including clothing and carry-on baggage. But passengers …
  3. Stats

    Among 15,378 Delta airline passengers randomly selected, 3 were bumped from a flight against there wishes (based on data from the us dept of transportation) find the probability that a random selected passenger is involuntarily bumped. …
  4. statistics

    on the daily run of an express bus, the average number of passengers is 48. the standard deviation is 3. Assume the variable is normally distributed. find the probability that the bus will have. a) between 36 and 40 passengers b) fewer …
  5. statistics

    The Ace AirLines has a policy of overbooking flights. The random variable x represents the number of passengers who cannot be boarded because there were more passengers that seats. x P(x) 0 0.061 1 0.132 2 0.255 3 0.345 4 0.207 a)Is …
  6. Statistics

    Suppose that the population of weights of airline passengers has mean 150 lbs. and standard deviation 25 lbs. A certain plane has a capacity of 7,800 lbs. (a) What is the probability that a flight of 50 passengers will exceed capacity …
  7. stats.

    The mean number of bumped airline passengers per day is 1.35 and the standard deviation is 0.25. For a random selection of a group of 40 days, what is the probability that the mean of bumped passengers for the 40 days will be between …
  8. stats.

    The mean number of bumped airline passengers per day s 1.35 and the standard deviation is 0.25. For a random selection of a group of 40 days, what is the probability that the mean number of bumped passengers for the 40 days will be …
  9. college stats

    help please!!! 1. The average number of bumped passengers per day on FliRite Airlines is 2.47 with a standard deviation of 1.75. For a random sample of 40 days, what is the chance the average number of bumped passengers in the sample …
  10. probability

    what is the probability of being bumped from a flight with 15,378 passengers selected and 3 were bumped?

More Similar Questions