Post a New Question


posted by .

3.14M NaN3 (pKb=9.28) is titrated with .663M HClO4 until it reaches the equivalence point. How do you calculate the pOH at the equivalence point.

I tried and got something around 9 but its not correct i used a table but without liters given i have not idea where to go or what to do. Please help!

  • chemisty -

    Do you have an equation for the titration?

  • chemisty -

    H^+ + N3- = HN3

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question