posted by Brittany jones .
How do you sole this problem: how many grams of CaCl2 are needed to prepare 7.25 L of .015M solution?
Molarity=moles/volume (L)=0.015= x moles/7.25 L
Solve for moles,
0.015*7.25L= moles of CaCl2 in solution
moles of CaCl2 in solution*(110.98 g/mol)= mass of CaCl2 in g.