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How do you sole this problem: how many grams of CaCl2 are needed to prepare 7.25 L of .015M solution?

  • chemistry -

    Molarity=moles/volume (L)=0.015= x moles/7.25 L

    Solve for moles,

    0.015*7.25L= moles of CaCl2 in solution

    moles of CaCl2 in solution*(110.98 g/mol)= mass of CaCl2 in g.

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