# Math (algerba 1)

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(4 X 10 to the -5th power) to the 2nd power.

How would I solve this?

• Math (algerba 1) -

Law of exponents says that you can distibute your power to when multiplying so you would have-

4^2 x 10^-10

I multiplied the two powers..

4^*1*2) x 10^(-5*2)

16 x 10^-10

I don't know if your teacher wants you to write this in a different form or not.

If could be 1.6 x 10^-9

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