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posted by Kyle Wednesday, March 13, 2013 at 5:54am.

Use intermediate value theorem to show there is a root to 2x^3 + x^2 - 2 = 0 on [0,1]

f(0) = -2 f(1) = 2+1-2 = 1 mmmhhh, how did the graph get from -2 to +1 ?

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