posted by Shane .
An observer on top of a building 66 metres high,finds the angle of elevation to the top of a taller building to be 34 degrees.The angle of depression to the foot of the same building is 51 degrees.If the buildings are on the same ground level find the height of the taller building.
tan51 = Y1/X = 66/X.
X = 66/tan51 = 53.4 m. = Distance between buildings.
tan34 = Y2/X = Y2/53.4
Y2 = 53.4*tan34 = 36.0 m.
h = Y1 + Y2 = 66 + 36 = 102.0 m. = Ht. of taller Bldg.