Applied Calculus
posted by Jacob .
If an open box has a square base and a volume of 112 in.3 and is constructed from a tin sheet, find the dimensions of the box, assuming a minimum amount of material is used in its construction. (Round your answers to two decimal places.)
Height:
Length:
Width:

if side is x,
height is 112/x^2
area
a = x^2 + 4xh
= x^2 + 4x(112/x^2)
= x^2 + 28/x
da/dx = 2x  28/x^2
da/dx=0 when x^3 = 14
and so on