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Iodine is mainly found in water in the trioxide ion, I3 which is formed by the combination of molecular iodine, I2 and Iodide, I-, according to the equation:
I2(aq) +I-(aq) <----> I3(aq)

QUESTION: how does the system in the equilibrium seem to respond to the changes applied to it with respect to the distribution of iodine considering that I2 will partition between the two phases I2(aq) <--> I2 (varsol)?

  • Chemistry -

    I've never done this; however, if I2 partitions more easily to the varsol(which it will do) it would appear to me that it increases I2 in varsol which reduces I2 in the aqueous phase and that should shift the I2==>I3- equilibrium to the left.
    By the way, you meant to call I3^- triiodide in your opening remarks.

  • Chemistry -

    Thank you so much

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