Geometry
posted by Tony .
ƒ¡ is a circle with center O . A and B are points on ƒ¡ such that the sector AOB has perimeter 40 . What is the measure of ÚAOB (in radians) when the area of the sector AOB is maximized

Geometry 
Steve
perimeter = 2r+rθ = 40
r = 40/(θ+2)
a = 1/2 r^2 θ = 800θ/(θ+2)^2
da/dθ = 800(θ2)/(θ+2)^3
da/dθ = 0 when θ=2 for maximum area
Note that it doesn't really matter what p is; max area for a constant perimeter is when θ=2
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