posted by .

Evaluate \displaystyle \int_1^{10} \left(\sqrt{x} + 1\right)^3 dx - \int_1^{10} \left(\sqrt{x} - 1\right)^3 dx .

  • Calculus -


    For x > 0, you have

    (sqrt(x) + 1)^3 - (sqrt(x) - 1)^3 =

    6 x + 2

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra

    Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solve for s: h=(square root of 3)times s/2 Multiply both sides by 2. 2h = (sqrt 3)*s*2/2 which cancels the 2 on the right. 2h = (sqrt 3)*s Now divide …
  2. math calculus please help!

    l = lim as x approaches 0 of x/(the square root of (1+x) - the square root of (1-x) decide whether: l=-1 or l=0 or l=1 Let me make sure I understand the question. Do we have lim x->0 x/[sqrt(1+x) - sqrt(1-x)] ?
  3. Math Help please!!

    Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine …
  4. Calculus

    Please look at my work below: Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 …
  5. Calculus

    Evaluate the indefinite integral: 8x-x^2. I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))
  6. Algebra

    b=2, c+ sqrt of 13. Trying to find the length of the 3rd side. It is a right triangle with A on top, 2 on the right side and the sqrt of 13 on the left.
  7. Calculus

    "Leave the answer as a definite integral, but indicate how it could by evaluated by using the fundamental theorem of calculus." I solved the problem to a definite integral. Proceeding via the fundamental theorem, would involve finding …
  8. Math

    Solve the puzzle =RIGHT(LEFT($B$2,84),1) =RIGHT(LEFT($B$2,17),1) =RIGHT(LEFT($B$2,138),1) =RIGHT(LEFT($B$2,2),1) =RIGHT(LEFT($B$2,234),1) =RIGHT(LEFT($B$2,138),1) =RIGHT(LEFT($B$2,4),1) =RIGHT(LEFT($B$2,173),1) =RIGHT(LEFT($B$2,2),1) …
  9. Simple Calculus

    Evaluate \displaystyle \lim_{x \to 0} \frac{\sqrt{2}x}{\sqrt{2+x}-\sqrt{2}}.
  10. Algebra

    Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work. sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2) x*sqrt 7x-49*x ^^^ would this be my final answer?

More Similar Questions