# Calculus

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Evaluate \displaystyle \int_1^{10} \left(\sqrt{x} + 1\right)^3 dx - \int_1^{10} \left(\sqrt{x} - 1\right)^3 dx .

• Calculus -

Hint:

For x > 0, you have

(sqrt(x) + 1)^3 - (sqrt(x) - 1)^3 =

6 x + 2

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