Geometry Inscribed
posted by Rose .
line BC is tangent to circle A at B and to circle D at C (not drawn to scale) AB=11, BC=23,and DC=2. find AD to the nearest tenth.
Image: i.imgur(dot)com/f4ThxTu.jpg

I looked at your diagram and noticed that you sketched a line from D to AB
That was good, now let the point of contact be E
so clearly triangle ADE is rightangled
with AE = 9 and DE = 23
by Pythagoras:
AD^2 = 9^2 + 23^2 = 610
AD = √610 = appr 24.7