calculus
posted by MIKE9999 .
∫1(3e^x+3x^2 )dx
0

I guess you mean integral from 0 to one
[ 3 e^x + x^3 ] at x = 1  at x = 0
at x = 1
3 e^1 + 1 = 3e+1
at x = 0
3 e^0 + 0 = 3
so in the end
3 e  2
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