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Calculate the pH of a solution made by adding 3.20 g of lithium oxide (Li2O) to enough water to make 1.210 L of solution. (Kw = 1.0 10-14)

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Li2O + H2O ==> 2LiOH
mols Li2O = 3.20/1.21 = ?
mols Li2O = 2 mols LiOH.
M LiOH = mols LiOH/L LiOH

Then (H^+)(OH^-) = 1E-14
Solve for (H^+), then
pH = -log(H^+)

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