posted by Sabrina .
Calculate the volume of 1.0 M copper(II) sulfate solution required to completely react with 1.0 g of Fe(s) according to this equation: 2 Fe(s) + 3 Cu^2+ (aq) --> 2 Fe^3+ (aq) + 3 Cu (s).
the copper in the reactant has a charge of 2+ and the iron in the product has a charge of 3+..sorry for the confusion. can anyone walk me through this? I'm unsure where to begin.
mols Fe = grams/atomic mass
Use the coefficients in the balanced equation to convert mols Fe to mols Cu^2+ (i.e. CuSO4).
Then M CuSO4 = mols CuSO4/L CuSO4. You have M and mols, solve for L. Convert to mL if needed.