Divide 3n^2-n/n^2-1/n^2/n+1
I am having trouble figuring out the problem. Could you re-enter it with ( ) for things that go together or tell me if I am right..
I am reading this as (3n^2-n)/(n^2-1)/(n^2)/(n+1)
Can't re-enter because that's how it 's written.
Where did you get it written like that?
On paper is it fraction over fraction over fraction over fraction?
If so, when you enter it here, you need ( ) for each separate part of the fraction otherwise it could be interpreted as
3n^2 subtract n divided by n^2 etc.
To divide the given expression, 3n^2-n/n^2-1/n^2/n+1, we can follow a set of steps:
Step 1: Simplify the expression within the numerator, 3n^2 - n.
Step 2: Simplify the expression within the denominator, n^2 - 1.
Step 3: Divide the result from Step 1 by the result from Step 2.
Step 4: Simplify the expression within the denominator, n^2.
Step 5: Finally, divide the result from Step 3 by the result from Step 4.
Let's solve each step individually:
Step 1: Simplify the numerator, 3n^2 - n:
To simplify, we can factor out the common term, n, from both terms and get:
n(3n - 1)
Step 2: Simplify the denominator, n^2 - 1:
This is a difference of squares. It can be factored as (n - 1)(n + 1).
Step 3: Divide the numerator by the denominator (after factoring):
We have the expression n(3n - 1)/(n - 1)(n + 1).
Step 4: Simplify the denominator further, n^2:
We can see that (n - 1)(n + 1) can be simplified as (n^2 - 1).
Step 5: Finally, divide the numerator by the simplified denominator:
We are left with the expression n(3n - 1)/(n^2 - 1).
So, the answer to the division problem 3n^2 - n/n^2 - 1/n^2/n + 1 is n(3n - 1)/(n^2 - 1).