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A projectile is launched at a 60 degree angle above the horizontal with an initial velocity of 35.5 m/s. What is the projectile's velocity (magnitude and direction) 1.50 s into the flight?

  • physics -

    Vo = 35.5m/s @ 60o.
    Xo = 35.5*cos60 = 17.75 m/s.
    Yo = 35.5*sin60 = 30.74 m/s.

    Y = Yo + g*t
    Y = 30.74 - 9.8*1.5 = 16.04 m/s.

    tanA = Y/Xo = 16.04/17.75 = 0.90366
    A = 42.1o

    V=Xo/cosA=17.75/cos42.1=23.9 m/s.@42.1o.

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