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A package slides down a 135 m long ramp with no friction. If the package starts from rest at the top and is to have a speed no faster than 19m/s at the bottom, what should be the maximum angle of inclination?

  • physics -

    (1/2) M Vmax^2 = M*g*135 sinA

    M cancels out.

    sinA = (1/2)Vmax^2/(g*135)
    = 0.1364
    A = 7.84 degrees

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