calculus
posted by tim2222 .
Use the second derivative to determine the point of inflection for y = x3 – x2 – 8x + 12. ????

y' = 3x^2  2x  8
y '' = 6x  2
at the point of inflection y'' = 0
6x2 = 0
x = 2/6 = 1/3
if x=1/3
y = 1/27  1/9  8/3 + 12
= 250/27
the point of inflection is (1/3 , 250/27)
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