calculus

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Use the second derivative to determine the point of inflection for y = x3 – x2 – 8x + 12. ????

  • calculus -

    y' = 3x^2 - 2x - 8
    y '' = 6x - 2

    at the point of inflection y'' = 0
    6x-2 = 0
    x = 2/6 = 1/3

    if x=1/3
    y = 1/27 - 1/9 - 8/3 + 12
    = 250/27

    the point of inflection is (1/3 , 250/27)

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