calculus
posted by tim2222 .
Use the second derivative to determine the point of inflection for y = x3 – x2 – 8x + 12. ????

calculus 
Reiny
y' = 3x^2  2x  8
y '' = 6x  2
at the point of inflection y'' = 0
6x2 = 0
x = 2/6 = 1/3
if x=1/3
y = 1/27  1/9  8/3 + 12
= 250/27
the point of inflection is (1/3 , 250/27)
Respond to this Question
Similar Questions

calc
one more question!! what values of c deos the polynomial f(x) = x^4 + cx^3 + x^2 have two inflection points? 
calculus
Use the second derivative to determine the point of inflection for y = x3 – x2 – 8x + 12. ? 
calculus
Use the second derivative to determine the point of inflection for y = x3 – x2 – 8x + 12. ? 
calculus
Use the second derivative to determine the point of inflection for y = x3 – x2 – 8x + 12. ? 
Calculus answer check
A brand new stock is also called an initial public offering. This model predicts the percent overvaluation of a stock as R(t)=9t((t3)^3/2.718) where is the overvaluation in percent and t is the time in months after the initial issue. … 
Calculus
For f(x)=2(x+5)^3 +7 Find and classify the extreme values, determine where the function is increasing and decreasing, where it is concave up and concave down, and any points of inflection. I understand this is using the first and second … 
Calculus
Find the xcoordinates of any relative extrema and inflection point(s) for the function f(x) = 3x^(1/3) + 6x^(4/3). You must justify your answer using an analysis of f '(x) and f "(x). I found the first and second derivative which … 
Differential Calculus
Determine all local extrema, concavity and inflection point/s for y = 2cos(x) in (0, 2Pi). Test by both First Derivative Test and Second Derivative Test and sketch the graph. 
AP Calculus
Suppose that f has a continuous second derivative for all x, and that f(0)=1, f'(0)=2, and f''(0)=0. A. Does f have an inflection point at x=0? 
calculus
how do I graph this using the first and second derivative and three sign charts. i have to label the inflection point, extreme values and the intercepts also. f(x)= x^36x^2