geometry!
posted by Anonymous...urgent! .
ABC is an acute angle triangle with points D and E on BC and AC, respectively such that BE and AD are altitudes. AD and BE intersect at H. If ∠BCA=39∘ and ∠EBA=2∠DAB, what is the measure of ∠ABC (in degrees)?

We have a bunch of right triangles here
BCA=39, so CAD = 51
BEA=90, so EHA = 39
vertical angle DHB is thus 39
HDB = 90, so HBD = 51
Now we know all the angles
A = 51+x
B = 51+2x
so, 39+51+x+51+2x = 180
x = 13
ABC = 26 
85
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