chemistry dilution

posted by .

Given VLP with concentration 200ug/mL, dilute to 3ug/100ul.

Please help me with this; many thanks

  • chemistry dilution -

    Add 6.67 x 10^1 mL of solvent to 1mL of stock.

    Converting everything to ug/mL, 200/3 =6.67 x 10^5 uL or 6.67 x 10^1 mL

    200ug/(6.67 x 10^5 mL +1 mL)= 2.96ug/mL

  • chemistry dilution -


    Add 6.67 x 10^1 mL of solvent to 1mL of stock.

    Converting everything to ug/mL, 200/3 =6.67 x 10^1 mL

    200ug/(6.67 x 10^1 mL +1 mL)= 2.96ug/mL

  • chemistry dilution -

    Did it again,

    Add 5.67mL of solvent to 1mL of stock to get a total volume of 6.67mL.

    Converting everything to ug/mL, 200/30 =6.67mL

    200ug/(5.67mL +1 mL)= 29.9ug/mL

  • chemistry dilution -

    This is a confusing problem.
    Here is another approach.
    We have a soln that is 200 ug/mL.
    We want 3 ug/100 uL. That is
    0.003 ug/uL = 3 ug/mL
    Say we want to make 100 mL of this solution, then 3 ug/mL x 100 mL = 300 ug we need.
    200 ug/mL x ?mL =300 ug
    ?mL = 300/200 = 1.5 mL;
    Therefore 1.5 mL of the 200 ug/mL solution and dilute that to 100 mL to make 300 ug/100 mL (which is 3 ug/mL). I think this is easier than measuring 5.67 mL of anything, expecially since we could use a 100 mL volumetric flask.

  • chemistry dilution -

    That is way easier, but I thought this may just be a homework problem and not a lab/research problem. So, I thought this would suffice. But, if you have to keep doing this dilution using 1.5mL compared to 1 mL of solution can get expensive, especially when research funds get tight or your PI has a bird mentality like mines did; cheap, cheap, cheap.

  • chemistry dilution -

    And I think one of us messed up. Either it should be 3ug/mL or 30ug/mL. When I punch in your numbers I get 15mL not 1.5mL.

    My work:

    3ug/100uL=3 x 10^-2 ug/uL

    3 x 10^-2 ug/uL*(1uL/10^-3mL)= 3 x10^1 ug/mL=30ug/mL.

    I could be wrong though.

  • chemistry dilution -

    thanks Devron and DrBo222

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry (please check/help)

    How would you make a serial dilution if you have a starting value 100mM of X The are the values of X show different dilutions. Volume variables (x) mL 0 1 3 1 10 30 100 We starting out with 100mM of X which would be considered its …
  2. bobpursley

    I don't really understand what you mean by "factors"... factors of 2 and factors of 3?
  3. BioChem

    If you want to determine the actual salicylate concentration for a sample that gives you a darker color than the highest standard, you would need to make a dilution of it. If you dilute it by mixing .25 mL of sample with .75 mL of …
  4. Dilution

    Please, if possible, check if my method of dilution is correct Problem: Given a very concentrated liquid PBS, dilute it to 1:15,000 My approach is to use serial dilution First: dilute it 15x (50ul of PBS + 750ul of water)... this will …
  5. chemistry

    Please help me with this dilution. Given a very concentrated tube of virus. Apply serial dilution to make 1:7500 dilution. Dilute virus in PBS
  6. dilution please help

    How to use serial dilution to dilute a stock solution at 15000 fold dilution?
  7. Chemistry

    Given a very concentrated glycercol solution. Dilute it to 7.5 fold dilution. How do I do this ?
  8. Clinical Chemistry

    I am not sure how to start this. You are given a 200% solution of a compound. You must dilute and construct a calibration curve to interpret concentration of compound in unknown samples. Show the steps needed to perform a two-fold …
  9. chemistry

    if i have a 21% solution of a product, and i need to make it a 9% solution of the same product what do i do?
  10. Biology

    You begin with 10 ml of 2% acetic acid, and you add 90 ml of water. We will call the resulting solution "dilution#1". What is its concentration?

More Similar Questions