posted by Sam .
You prepare a solution from 10.0 mL of 0.100 M MOPS buffer (3-morpholinopropane-1-sulfonic acid) and 10.0 mL of 0.086 M NaOH. Next, you add 1.00 mL of 8.87 × 10-4 M lidocaine to this mixture Denoting lidocaine as L, calculate the fraction of lidocaine present in the form LH .
Analytical Chemistry -
This is what I think, but I can not be sure.
0.001 moles of MOPS buffer
0.00086 moles of NaOH
1.4 x 10^-4 moles of MOPS left to react with L
1.4 x10^-4/total volume =6.67 x 10^-3 M of MOPS
8.87 x 10^-7 moles of L/total volume=4.2 x 10^-5 M for L
HA + L--> A + LH
8.7 x 10^-7=x^2/(6.67 x 10^-3 M)(4.22 x 10^-5 M)
x=4.95 x 10^-7
4.95 x 10^-7/4.2 x 10^-5 M =1.17x 10-2
Once again I am not sure!!!!!!