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Three resistors, 1.17, 2.84, and 3.65Ω, are connected in series across a 20.3-V battery. Find the power delivered to each resistor.

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    R=R₁+R₂+R₃=1.17+2.84+3.65 =7.66 Ω
    I=U/R = 20.3/7.66=2.65 A
    P₁ =I²R₁=2.65²•1.17=
    P₂ =I²R₂=2.65²•2.84=
    P₃=I²R₃=2.65²•3.65=

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