Find an integer value of x such that when 3x−39 is divided by 2x, the quotient is 1 and the remainder is 50.
(3x-39)/2x = 1 + 50/2x
3x-39 = 2x + 50
x = 89
Check:
3*89-39 = 228
228/178 = 1 R 50
3x-39 = 2x + 50
x = 89
Check:
3*89-39 = 228
228/178 = 1 R 50