Calculus
posted by Jilian .
The equation of motion of a particle is s= 2y^3  7t^2 + 4t +1 where s is in meters and t is in seconds
a) Find the velocity and acceleration as functions of t.
b) Find the acceleration after 1 second.

are you sure that is 2y^3 and not 2 t^3 ?
2 y^3 is all right, but unusual and probably not intended. 
If as typed, the 2y^3 has nothing to do with the velocity and acceleration
v =ds/dt = 14 t + 4
a = dv/dt = 14
If as I kind of have a hunch you mean
v = 6 t^2  14 t + 4
a = 12 t  14 
it was 2 t^3
Thanks
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